Compare dictionaries ignoring specific keys

def equal_dicts(d1, d2, ignore_keys):
    d1_filtered = {k:v for k,v in d1.items() if k not in ignore_keys}
    d2_filtered = {k:v for k,v in d2.items() if k not in ignore_keys}
    return d1_filtered == d2_filtered

EDIT: This might be faster and more memory-efficient:

def equal_dicts(d1, d2, ignore_keys):
    ignored = set(ignore_keys)
    for k1, v1 in d1.iteritems():
        if k1 not in ignored and (k1 not in d2 or d2[k1] != v1):
            return False
    for k2, v2 in d2.iteritems():
        if k2 not in ignored and k2 not in d1:
            return False
    return True