You could use the grep option -o, possibly in combination with changing your pattern to “.{0,10}<original pattern>.{0,10}” in order to see some context around it: -o, –only-matching Show only the part of a matching line that matches PATTERN. ..or -c: -c, –count Suppress normal output; instead print a count of matching lines for each input … Read more
try: grep -n “text to find” file.ext | cut -f1 -d:
Why do you pass -c? That will just show the number of matches. Similarly, there is no reason to use -r. I suggest you read man grep. To grep for 2 words existing on the same line, simply do: grep “word1” FILE | grep “word2” grep “word1” FILE will print all lines that have word1 … Read more
You need to use find instead of grep in this case. You can also use find in combination with grep or egrep: $ find | grep “f[[:alnum:]]\.frm”
grep -l (That’s a lowercase L)
You can use the -s or –no-messages flag to suppress errors. -s, –no-messages suppress error messages grep pattern * -s -R -n
This works for multiple occurrences per line: grep -o string * | wc -l
grep -n SEARCHTERM file1 file2 …
-m 1 means return the first match in any given file. But it will still continue to search in other files. Also, if there are two or more matched in the same line, all of them will be displayed. You can use head -1 to solve this problem: grep -o -a -m 1 -h -r … Read more
Try grep -o: grep -oh “\w*th\w*” * Edit: matching from Phil’s comment. From the docs: -h, –no-filename Suppress the prefixing of file names on output. This is the default when there is only one file (or only standard input) to search. -o, –only-matching Print only the matched (non-empty) parts of a matching line, with each … Read more