You may want to re-read The Rust Programming Language, specifically the sections on: mutability mutable references vectors We can also iterate over mutable references to each element in a mutable vector in order to make changes to all the elements. The for loop in Listing 8-9 will add 50 to each element. let mut v … Read more
There is no way to return a value from forEach. Just use a for loop instead. bool nameExists(players, player) { for(var f in players) { if (f.data[‘name’].toLowerCase() == player.toLowerCase()) { return true; } } return false; }
There is no need to use find. You could try the following: for file in /path/to/directory/**/*(.); do echo $file; done or for file in /path/to/directory/**/*(.); echo $file the ** pattern matches multiple directories recursively. So a/**/b matches any b somewhere below a. It is essentially matches the list find a -name b produces. (.) is … Read more
Based on the other answers, I think the cleanest solutions are #Handles None return from get_list for item in get_list() or []: pass #do something or the comprehension equiv result = [item*item for item in get_list() or []]
In Kotlin you can use this syntax: for (a in 1..10) print(“$a “) // >>> 1 2 3 4 5 6 7 8 9 10 for (a in 10 downTo 1 step 2) print(“$a “) // >>> 10 8 6 4 2 As for “why was the indexed loop removed” – scroll down for @yole’s … Read more
Either use return, as the closure basically is a method that is called with each element as parameter like def myObj = [“Hello”, “World!”, “How”, “Are”, “You”] myList.each{ myObj-> if(myObj==null){ return } println(“My Object is ” + myObj) } Or switch your pattern to def myObj = [“Hello”, “World!”, “How”, “Are”, “You”] myList.each{ myObj-> if(myObj!=null){ … Read more
ipairs() and pairs() are slightly different, as you can see on the manual reference. A less-technical description could be that: ipairs() returns index-value pairs and is mostly used for numeric tables. The non-numeric keys are ignored as a whole, similar to numeric indices less than 1. In addition, gaps in between the indexes lead to … Read more
A forward loop is like this: for x in 0..100 { println!(“{}”, x); } And a reverse loop is done by calling Iterator::rev to reverse the order: for x in (0..100).rev() { println!(“{}”, x); }
for(;;) { } functionally means while (true) { } It will probably break the loop/ return from loop based on some condition inside the loop body. The reason that for(;;) loops forever is because for has three parts, each of which is optional. The first part initializes the loop; the second decides whether or not … Read more
This is because there is only a single loop variable chart, and in each iteration just a new value is assigned to it. So if you attempt to take the address of the loop variable, it will be the same in each iteration, so you will store the same pointer, and the pointed object (the … Read more