It’s easier to understand if you rewrite that as the completely equivalent
// v───v───v───v───v───v───v───v───v───v───v───v─┬┐
// ││
// v──#1 v─#2 v──#3 v─#4 #5
int const * const Method3(int const * const&) const;
then read it from right to left.
#5 says that the entire function declaration to the left is const, which implies that this is necessarily a member function rather than a free function.
#4 says that the pointer to the left is const (may not be changed to point to a different address).
#3 says that the int to the left is const (may not be changed to have a different value).
#2 says that the pointer to the left is const.
#1 says that the int to the left is const.
Putting it all together, you can read this as a const member function named Method3 that takes a reference to a const pointer to an int const (or a const int, if you prefer) and returns a const pointer to an int const (const int).
(N.b. #2 is entirely superfluous.)