It seems like there is no other way since java.Lang.Number doesn’t have a method which returns a BigDecimal type. Anyway it makes sense because BigDecimal only accepts strings which are properly formatted not like "2.105,88" but like "2105.88".
Let me show your my code:
import java.math.BigDecimal;
import java.text.DecimalFormat;
import java.text.NumberFormat;
import java.text.ParseException;
import java.util.Locale;
public class JavaMain {
public static void main(String[] args) {
String numberString = "2.105,88";
//using casting
try {
DecimalFormat df = (DecimalFormat) NumberFormat.getInstance(Locale.GERMAN);
df.setParseBigDecimal(true);
BigDecimal bd = (BigDecimal) df.parseObject(numberString);
System.out.println(bd.toString());
} catch (ParseException e) {
e.printStackTrace();
}
//your way short version
NumberFormat nf = NumberFormat.getInstance(Locale.GERMAN);
try {
BigDecimal bd1 = new BigDecimal(nf.parse(numberString).toString());
System.out.println(bd1.toString());
} catch (ParseException e) {
e.printStackTrace();
}
String numberStringFixed = "2105.88";
//direct string formatted
System.out.println(new BigDecimal(numberStringFixed));;
//direct but erroneous way if the string is not formatted
System.out.println(new BigDecimal(numberString));;
}
}
I hope this helps!