Behavior-wise, yes they are equivalent since the member access -> operator has a higher precedence than the address-of & operator.
Readibility-wise, the second one &(s->var) is much more readable than &s->var and should be preferred over the first form. With the second form, &(s->var), you won’t have to second-guess what it’s actually doing as you know the expression in the parentheses are always evaluated first. When in doubt, use parentheses.