Yes, it’s just -- instead of --args. From the help:
lldb -v [[--] <PROGRAM-ARG-1> [<PROGRAM_ARG-2> ...]]
Thus:
$ lldb -- exe --lots --of --flags -a -b -c d e
Yes, it’s just -- instead of --args. From the help:
lldb -v [[--] <PROGRAM-ARG-1> [<PROGRAM_ARG-2> ...]]
Thus:
$ lldb -- exe --lots --of --flags -a -b -c d e