What is the difference between int and int64 in Go?

Question

func ParseInt(s string, base int, bitSize int) (i int64, err error)

ParseInt always returns int64.

bitSize defines the range of values.

If the value corresponding to s cannot be represented by a signed integer of the given size, err.Err = ErrRange.

http://golang.org/pkg/strconv/#ParseInt

type int int

int is a signed integer type that is at least 32 bits in size. It is a distinct type, however, and not an alias for, say, int32.

http://golang.org/pkg/builtin/#int

So int could be bigger than 32 bit in the future or on some systems like int in C.

I guess on some systems int64 might be faster than int32 because that system only works with 64-bit integers.

Here is an example of an error when bitSize is 8:

http://play.golang.org/p/_osjMqL6Nj

package main

import (
    "fmt"
    "strconv"
)

func main() {
    i, err := strconv.ParseInt("123456", 10, 8)
    fmt.Println(i, err)
}