Using multiple let-as within a if-statement in Swift

Update for Swift 3:

The following will work in Swift 3:

if let latitudeDouble = latitude as? Double, let longitudeDouble = longitude as? Double {
    // latitudeDouble and longitudeDouble are non-optional in here
}

Just be sure to remember that if one of the attempted optional bindings fail, the code inside the if-let block won’t be executed.

Note: the clauses don’t all have to be ‘let’ clauses, you can have any series of boolean checks separated by commas.

For example:

if let latitudeDouble = latitude as? Double, importantThing == true {
    // latitudeDouble is non-optional in here and importantThing is true
}

Swift 1.2:

Apple may have read your question, because your hoped-for code compiles properly in Swift 1.2 (in beta today):

if let latitudeDouble = latitude as? Double, longitudeDouble = longitude as? Double {
    // do stuff here
}

Swift 1.1 and earlier:

Here’s the good news – you can totally do this. A switch statement on a tuple of your two values can use pattern-matching to cast both of them to Double at the same time:

var latitude: Any! = imageDictionary["latitude"]
var longitude: Any! = imageDictionary["longitude"]

switch (latitude, longitude) {
case let (lat as Double, long as Double):
    println("lat: \(lat), long: \(long)")
default:
    println("Couldn't understand latitude or longitude as Double")
}

Update: This version of the code now works properly.