From the Python grammar, we can see that ; is not defined as \n. The parser expects another statement after a ;, except if there’s a newline after it: Semicolon w/ statement Maybe a semicolon Newline \/ \/ \/ \/ simple_stmt: small_stmt (‘;’ small_stmt)* [‘;’] NEWLINE That’s why x=42;; doesn’t work; because there isn’t a … Read more
You’ve told jQuery to expect a JSONP response, which is why jQuery has added the callback=jQuery16406345664265099913_1319854793396&_=1319854793399 part to the URL (you can see this in your dump of the request). What you’re returning is JSON, not JSONP. Your response looks like {“red” : “#f00”} and jQuery is expecting something like this: jQuery16406345664265099913_1319854793396({“red” : “#f00”}) If … Read more
The expressions 0.0 and 00.0 are parsed differently. 0.0 is parsed as a numeric literal 1 00.0 is parsed as: 00 – octal numeric literal 2 . – property accessor 0 – identifier name Your code throws syntax error because 0 is not a valid JavaScript identifier. The following example works since toString is a … Read more
The problem is that the class extends native ES6 class and is transpiled to ES5 with Babel. Transpiled classes cannot extend native classes, at least without additional measures. class TranspiledFoo extends NativeBar { constructor() { super(); } } results in something like function TranspiledFoo() { var _this = NativeBar.call(this) || this; return _this; } // … Read more
As suggested by Josh Lee in the comment section, that kind of string interpolation was added in Python 3.6 only, see What’s New In Python 3.6 (here it’s called “PEP 498: Formatted string literals”). You, however, seems to be using Python 3.5.2, which does not support that syntax.
This error occurs mostly when there are unclosed curly braces or when some fields are not properly defined while calling the query.
Your issue is the fact that the i in function is the unicode character i. If you change it to a ‘normal’ i it should just work. But now I’m wondering how the hack 🙂 did you get an unicode character there 😛
return only makes sense inside a function. There is no function in your code. Also, your code is worthy if the Department of Redundancy Department. Assuming you move it to a proper function, this would be better: return confirm(“.json_encode($message).”); EDIT much much later: Changed code to use json_encode to ensure the message contents don’t break … Read more
Change $data[$parts[0]] = $parts[1]; to if ( ! isset($parts[1])) { $parts[1] = null; } $data[$parts[0]] = $parts[1]; or simply: $data[$parts[0]] = isset($parts[1]) ? $parts[1] : null; Not every line of your file has a colon in it and therefore explode on it returns an array of size 1. According to php.net possible return values from … Read more
TL;DR Error #1064 means that MySQL can’t understand your command. To fix it: Read the error message. It tells you exactly where in your command MySQL got confused. Examine your command. If you use a programming language to create your command, use echo, console.log(), or its equivalent to show the entire command so you can … Read more