NSString *string = @”hello bla bla”; if ([string rangeOfString:@”bla”].location == NSNotFound) { NSLog(@”string does not contain bla”); } else { NSLog(@”string contains bla!”); } The key is noticing that rangeOfString: returns an NSRange struct, and the documentation says that it returns the struct {NSNotFound, 0} if the “haystack” does not contain the “needle”. And if … Read more
>>> x = “Hello World!” >>> x[2:] ‘llo World!’ >>> x[:2] ‘He’ >>> x[:-2] ‘Hello Worl’ >>> x[-2:] ‘d!’ >>> x[2:-2] ‘llo Worl’ Python calls this concept “slicing” and it works on more than just strings. Take a look here for a comprehensive introduction.
Now with PHP 8 you can do this using str_contains: if (str_contains(‘How are you’, ‘are’)) { echo ‘true’; } RFC Before PHP 8 You can use the strpos() function which is used to find the occurrence of one string inside another one: $a=”How are you?”; if (strpos($a, ‘are’) !== false) { echo ‘true’; } Note … Read more
You can use Marcus’s answer (* wildcards) outside a case statement, too, if you use double brackets: string=’My long string’ if [[ $string == *”My long”* ]]; then echo “It’s there!” fi Note that spaces in the needle string need to be placed between double quotes, and the * wildcards should be outside. Also note … Read more
Use the in operator: if “blah” not in somestring: continue