More than 1 row in
Why not use the <textarea> tag? <textarea id=”txtArea” rows=”10″ cols=”70″></textarea>
Why not use the <textarea> tag? <textarea id=”txtArea” rows=”10″ cols=”70″></textarea>
Try using fetchone: cursor.execute(“SELECT COUNT(*) from result where server_state=”2″ AND name LIKE ‘”+digest+”_”+charset+”_%'”) result=cursor.fetchone() result will hold a tuple with one element, the value of COUNT(*). So to find the number of rows: number_of_rows=result[0] Or, if you’d rather do it in one fell swoop: cursor.execute(“SELECT COUNT(*) from result where server_state=”2″ AND name LIKE ‘”+digest+”_”+charset+”_%'”) (number_of_rows,)=cursor.fetchone() … Read more
This should do the trick: df[- grep(“REVERSE”, df$Name),] Or a safer version would be: df[!grepl(“REVERSE”, df$Name),]
You can do it that way: # for Python 2 df.index = df.index.map(unicode) # for Python 3 (the unicode type does not exist and is replaced by str) df.index = df.index.map(str) As for why you would proceed differently from when you’d convert from int to float, that’s a peculiarity of numpy (the library on which … Read more
(“#tblEntAttributes tbody”) needs to be $(“#tblEntAttributes tbody”). You are not selecting the element with the correct syntax Here’s an example of both $(newRowContent).appendTo($(“#tblEntAttributes”)); and $(“#tblEntAttributes tbody”).append(newRowContent); working http://jsfiddle.net/xW4NZ/
df[df$aged <= df$laclen, ] Should do the trick. The square brackets allow you to index based on a logical expression.
Yes, SELECT COUNT(*) FROM TableName
What about creating a startup script with SET NOCOUNT ON in the script (assign the script to the SQLCMDINI environment variable). http://msdn.microsoft.com/en-us/library/ms162773.aspx
select distinct stuff(( select ‘,’ + u.username from users u where u.username = username order by u.username for xml path(”) ),1,1,”) as userlist from users group by username had a typo before, the above works
df <- data.frame(a = 1:2, b = letters[1:2]) df[rep(seq_len(nrow(df)), each = 2), ]