You could pass a model object to the partial (for example a list of strings): <% Html.RenderPartial(“~/controls/users.ascx”, new string[] { “foo”, “bar” }); %> Then you strongly type the partial and the Model property will be of the appropriate type: <%@ Control Language=”C#” Inherits=”System.Web.Mvc.ViewUserControl<System.Collections.Generic.IEnumerable<string>>” %> <% foreach (var item in Model) { %> <div><%= Html.Encode(item) … Read more
Html.Partial(“MyView”) Renders the “MyView” view to an MvcHtmlString. It follows the standard rules for view lookup (i.e. check current directory, then check the Shared directory). Html.RenderPartial(“MyView”) Does the same as Html.Partial(), except that it writes its output directly to the response stream. This is more efficient, because the view content is not buffered in memory. … Read more
You are getting this error because Html.RenderXXX helpers return void – they have nothing to return because they are writing stuff directly* to response. You should use them like this: @{ Html.RenderPartial(“_Test”); } There is also Html.Partial helper, which will work with your syntax, but I’d not recommend using it unless you have to, because … Read more
Andrew I think the problem you are getting is a result of the RenderPartial method using the calling (view)’s model to the partial view when the model you pass is null.. you can get around this odd behavior by doing: <% Html.RenderPartial(“TaskList”, Model.Tasks, new ViewDataDictionary()); %> Does that help?
You can’t render a partial view using only jQuery. You can, however, call a method (action) that will render the partial view for you and add it to the page using jQuery/AJAX. In the below, we have a button click handler that loads the url for the action from a data attribute on the button … Read more
Just include the path to the view, with the file extension. Razor: @Html.Partial(“~/Views/AnotherFolder/Messages.cshtml”, ViewData.Model.Successes) ASP.NET engine: <% Html.RenderPartial(“~/Views/AnotherFolder/Messages.ascx”, ViewData.Model.Successes); %> If that isn’t your issue, could you please include your code that used to work with the RenderUserControl?
Html.Partial returns a String. Html.RenderPartial calls Write internally and returns void. The basic usage is: // Razor syntax @Html.Partial(“ViewName”) @{ Html.RenderPartial(“ViewName”); } // WebView syntax <%: Html.Partial(“ViewName”) %> <% Html.RenderPartial(“ViewName”); %> In the snippet above, both calls will yield the same result. While one can store the output of Html.Partial in a variable or return … Read more