Valid to the URI RFC Likely acceptable to your server-side framework/code The URI RFC doesn’t mandate a format for the query string. Although it is recognized that the query string will often carry name-value pairs, it is not required to (e.g. it will often contain another URI). 3.4. Query The query component contains non-hierarchical data … Read more
Use the urllib.parse library: >>> from urllib import parse >>> url = “http://www.example.org/default.html?ct=32&op=92&item=98″ >>> parse.urlsplit(url) SplitResult(scheme=”http”, netloc=”www.example.org”, path=”/default.html”, query=’ct=32&op=92&item=98′, fragment=””) >>> parse.parse_qs(parse.urlsplit(url).query) {‘item’: [’98’], ‘op’: [’92’], ‘ct’: [’32’]} >>> dict(parse.parse_qsl(parse.urlsplit(url).query)) {‘item’: ’98’, ‘op’: ’92’, ‘ct’: ’32’} The urllib.parse.parse_qs() and urllib.parse.parse_qsl() methods parse out query strings, taking into account that keys can occur more than once … Read more
You can navigate to the current route with new query params, which will not reload your page, but will update query params. Something like (in the component): import {ActivatedRoute, Router} from ‘@angular/router’; constructor( private router: Router, private activatedRoute: ActivatedRoute, ) { } public myMethodChangingQueryParams() { const queryParams: Params = { myParam: ‘myNewValue’ }; this.router.navigate( [], … Read more
They need to be percent-encoded: > encodeURIComponent(‘&’) “%26” So in your case, the URL would look like: http://www.mysite.com?candy_name=M%26M
Express 4.x To get a URL parameter’s value, use req.params app.get(‘/p/:tagId’, function(req, res) { res.send(“tagId is set to ” + req.params.tagId); }); // GET /p/5 // tagId is set to 5 If you want to get a query parameter ?tagId=5, then use req.query app.get(‘/p’, function(req, res) { res.send(“tagId is set to ” + req.query.tagId); }); … Read more
According to the docs of route object, you have access to a $route object from your components, which exposes what you need. In this case //from your component console.log(this.$route.query.test) // outputs ‘yay’