Using prepared statements, there is no “SQL query” : You have a statement, containing placeholders it is sent to the DB server and prepared there which means the SQL statement is “analysed”, parsed, some data-structure representing it is prepared in memory And, then, you have bound variables which are sent to the server and the … Read more
You need to set it in the value itself, not in the prepared statement SQL string. So, this should do for a prefix-match: notes = notes .replace(“!”, “!!”) .replace(“%”, “!%”) .replace(“_”, “!_”) .replace(“[“, “![“); PreparedStatement pstmt = con.prepareStatement( “SELECT * FROM analysis WHERE notes LIKE ? ESCAPE ‘!'”); pstmt.setString(1, notes + “%”); or a suffix-match: … Read more
The idea is very simple – the query and the data are sent to the database server separately. That’s all. The root of the SQL injection problem is in the mixing of the code and the data. In fact, our SQL query is a legitimate program. And we are creating such a program dynamically, adding … Read more
An analysis of the various options available, and the pros and cons of each is available in Jeanne Boyarsky’s Batching Select Statements in JDBC entry on JavaRanch Journal. The suggested options are: Prepare SELECT my_column FROM my_table WHERE search_column = ?, execute it for each value and UNION the results client-side. Requires only one prepared … Read more
You’ll have to construct the query-string. <?php $ids = array(1, 2, 3, 7, 8, 9); $inQuery = implode(‘,’, array_fill(0, count($ids), ‘?’)); $db = new PDO(…); $stmt = $db->prepare( ‘SELECT * FROM table WHERE id IN(‘ . $inQuery . ‘)’ ); // bindvalue is 1-indexed, so $k+1 foreach ($ids as $k => $id) $stmt->bindValue(($k+1), $id); $stmt->execute(); … Read more