It’s actually the statement after the one you mark as causing the program to crash that causes the program to crash! You must pass the same pointer to delete[] as you get back from new[]. Otherwise the behaviour of the program is undefined.
The Vector3.Normalize() method has a pointer receiver, so in order to call this method, a pointer to Vector3 value is required (*Vector3). In your first example you store the return value of Vector3.Minus() in a variable, which will be of type Vector3. Variables in Go are addressable, and when you write diff.Normalize(), this is a … Read more
A pointer has following advantages: a) You can do a lazy initialization, that means to init / create the object only short before the first real usage. b) The design: if you use pointers for members of an external class type, you can place a forward declaration above your class and thus don’t need to … Read more
The C standard does not allow to cast function pointers to void*. You may only cast to another function pointer type. In the C11 standard, 6.3.2.3 §8: A pointer to a function of one type may be converted to a pointer to a function of another type and back again Importantly, you must cast back … Read more
The most important thing is consistency. If there aren’t any coding guidelines for this, then pick one and stick with it. But, if your team already has a de facto standard, don’t change it! That said, I think by far the more common is const int * i; int * const j; because most people … Read more
Since c is holding the address of an integer pointer, its type should be int**: int **c; c = &a; The entire program becomes: #include <stdio.h> int main(){ int b=10; int *a; a=&b; int **c; c=&a; printf(“%d”,(**c)); //successfully prints 10 return 0; }
You want this: typedef void (K::*MemFuncType)() const; If you want to still base MemFuncType on FuncType, you need to change FuncType: typedef void FuncType() const; typedef FuncType K::* MemFuncType;
First of all b is an array, not a pointer, so it is not assignable. Also, you cannot cast anything to an array type. You can, however, cast to pointer-to-array. Note that in C and C++ pointer-to-arrays are rather uncommon. It is almost always better to use plain pointers, or pointer-to-pointers and avoid pointer-to-arrays. Anyway, … Read more
When t is used on its own in the expression, an array-to-pointer conversion takes place, this produces a pointer to the first element of the array. When t is used as the argument of the & operator, no such conversion takes place. The & then explicitly takes the address of t (the array). &t is … Read more
delete [] does know the size that was allocated. However, that knowledge resides in the runtime or in the operating system’s memory manager, meaning that it is not available to the compiler during compilation. And sizeof() is not a real function, it is actually evaluated to a constant by the compiler, which is something it … Read more