You can also render a PartialViewResult to a string, and then pass this string via JSON to your view, rendering it in your page using jQuery. You can see that in this post: http://www.atlanticbt.com/blog/asp-net-mvc-using-ajax-json-and-partialviews/. I’ve created an extension to make it easier: public static class MvcHelpers { public static string RenderPartialView(this Controller controller, string viewName, … Read more
Here, this is what I use in Controllers for ajax, I modified it a bit so it can be called from method instead of controller, method returnView renders your view and returns HTML string so you can insert it with JS/jQuery into your page when you recive it on client side: public static string RenderPartialToString(string … Read more
Partials are not the way to go here. You are looking for EditorTemplates, these are made for what you want. This case, your properties will be nicely bound to your model (that you will submit). Your main View will have this form (note that you only have to use EditorFor instead of Partial; in this … Read more
Because now you are serving your views from some unknown location there is no longer the ~/Views/web.config file which applies and indicates the base class for your razor views (<pages pageBaseType=”System.Web.Mvc.WebViewPage”>). So you could add an @inherits directive at the top of each embedded view to indicate the base class. @inherits System.Web.Mvc.WebViewPage @model …
Try this Without :locals and :partial .content = render ‘meeting_info’, :info => @info No need to specify locals. With :locals and :partial You should specify locals in following case i.e specifying :partial for render .content = render :partial => ‘meeting_info’, :locals => { :info => @info }
I believe you are correct. Here is an example of something I do, general navigation partial views in my Shared directory. and then a partial views for a specific Controller in the Views/[ControllerName] Directory.
You’re not actually passing the model to the Partial, you’re passing a new ViewDataDictionary<LetLord.Models.Tenant>(). Try this: @model LetLord.Models.Tenant <div class=”row-fluid”> <div class=”span4 well-border”> @Html.Partial(“~/Views/Tenants/_TenantDetailsPartial.cshtml”, Model) </div> </div>
Ruby allows you to do nice things like this: <%= render :partial => “foo/bar” if @conditions %> To make this a bit easier to read and understand, it can be written as: <%= render(:partial => “foo/bar”) if @conditions %> render is a function, and you pass it a hash that tells it which partial to … Read more
I had the same issue as the OP. From one of the comments, I realized that the second parameter shouldn’t be null, i.e from @model ParentViewModel @Html.Partial(“_Partial”, Model.Child) If Model.Child is null, then Model is passed instead of Model.Child. If there will be cases when the second parameter is null, then you will have to … Read more
Not without jQuery. What you would have to do is put your Partial in a div, something like: <div id=”partial”> @Html.Partial(“YourPartial”) </div> Then, to update (for example clicking a button with the id button), you could do: $(“#button”).click(function () { $.ajax({ url: “YourController/GetData”, type: “get”, data: $(“form”).serialize(), //if you need to post Model data, use … Read more