It’s converting null to the string “null” and trying to convert it. For radixes 0 through 23, there are no numerals it can convert, so it returns NaN. At 24, “n”, the 14th letter, is added to the numeral system. At 31, “u”, the 21st letter, is added and the entire string can be decoded. … Read more
Try Character.getNumericValue(char). String element = “el5”; int x = Character.getNumericValue(element.charAt(2)); System.out.println(“x=” + x); produces: x=5 The nice thing about getNumericValue(char) is that it also works with strings like “el٥” and “el५” where ٥ and ५ are the digits 5 in Eastern Arabic and Hindi/Sanskrit respectively.
Well, the API for Integer.valueOf(String) does indeed say that the String is interpreted exactly as if it were given to Integer.parseInt(String). However, valueOf(String) returns a new Integer() object whereas parseInt(String) returns a primitive int. If you want to enjoy the potential caching benefits of Integer.valueOf(int), you could also use this eyesore: Integer k = Integer.valueOf(Integer.parseInt(“123”)) … Read more
The result of 1/0 is Infinity. parseInt treats its first argument as a string which means first of all Infinity.toString() is called, producing the string “Infinity”. So it works the same as if you asked it to convert “Infinity” in base 19 to decimal. Here are the digits in base 19 along with their decimal … Read more