Android will make an exception when you change the view hierarchy in animationEnd. All you have to do is to postpone your call like this : @Override public void onAnimationEnd(Animation animation) { new Handler().post(new Runnable() { public void run() { myLayout.removeView(simulateMovingImg); } }); }
Your app is crashing at: welcomePlayer.setText(“Welcome Back, ” + String.valueOf(mPlayer.getName(this)) + ” !”); because mPlayer=null. You forgot to initialize Player mPlayer in your PlayGame Activity. mPlayer = new Player(context,””);
A NullPointerException means that one of the variables you are passing is null, but the code tries to use it like it is not. For example, If I do this: Integer myInteger = null; int n = myInteger.intValue(); The code tries to grab the intValue of myInteger, but since it is null, it does not … Read more
When you write value = condition ? null : 1.0; the type of condition ? null : 1.0 must be a reference type, so the type is Double, which can hold the value null. When you write value = condition ? getDouble() : 1.0; and getDouble() returns null, it’s equivalent to writing: value = condition … Read more
Try to replace the failing line with: mSearchMenuItem = menu.findItem(R.id.action_search); mSearchView = (EnglishVerbSearchView) MenuItemCompat.getActionView(mSearchMenuItem); Where R.id.action_search is the id of your search item in the menu. EDIT Your manifest should look like that: <activity android:name=”com.bronzelabs.twc.activities.WorkflowListActivity” android:label=”@string/app_name” android:theme=”@style/Theme.AppCompat.Light” > <intent-filter> <action android:name=”android.intent.action.MAIN” /> <category android:name=”android.intent.category.LAUNCHER” /> </intent-filter> </activity> <activity android:name=”.activities.SearchResultActivity” android:theme=”@style/Theme.AppCompat.Light” android:launchMode=”singleTop”> <intent-filter> <action android:name=”android.intent.action.SEARCH” /> … Read more
Your code makes use of two different additive operators. The first three lines use string concatenation, whereas the last one uses numeric addition. String concatenation is well-defined to turn null into “null”: If the reference is null, it is converted to the string “null” (four ASCII characters n, u, l, l). Hence there is no … Read more
test() is a static method. A static member belongs to the type, and do not require an instance to access. A static member should ONLY be accessed via a type expression. That is, you should’ve written it as follows: Why.test(); // always invoke static method on the type it belongs to! Java does allow you … Read more
The first invocation will call the String.valueOf(Object) method, as you have explicitly typecasted null to Object reference. Conversely, the second one will invoke the overloaded String.valueOf(char[]) method, as char[] is more specific than Object for a null argument. There are other overloaded versions of this method that accept primitive parameters, but those are not a … Read more
The reason is not to force null checks in client code, in consistency with Effective Java 2nd Edition, Item 43: Return empty arrays or collections, not nulls. This makes the client code simpler and less error-prone (and most likely the method implementation as well). The null-return idiom is likely a holdover from the C programming … Read more
Because statics are initialized in the order they are given in source code. Check this out: class MyClass { private static MyClass myClass = new MyClass(); private static MyClass myClass2 = new MyClass(); public MyClass() { System.out.println(myClass); System.out.println(myClass2); } } That will print: null null myClassObject null EDIT Ok let’s draw this out to be … Read more