NSArray* foo = [@”10/04/2011″ componentsSeparatedByString: @”https://stackoverflow.com/”]; NSString* firstBit = [foo objectAtIndex: 0]; Update 7/3/2018: Now that the question has acquired a Swift tag, I should add the Swift way of doing this. It’s pretty much as simple: let substrings = “10/04/2011”.split(separator: “https://stackoverflow.com/”) let firstBit = substrings[0] Although note that it gives you an array of … Read more
You could try this: CGRect textRect = [text boundingRectWithSize:size options:NSStringDrawingUsesLineFragmentOrigin attributes:@{NSFontAttributeName:FONT} context:nil]; CGSize size = textRect.size; Just change “FONT” for an “[UIFont font….]”
NSIntegers are not objects, you cast them to long, in order to match the current 64-bit architectures’ definition: NSString *inStr = [NSString stringWithFormat: @”%ld”, (long)month];
It looks like you are passing an NSString parameter where you should be passing an NSData parameter: NSError *jsonError; NSData *objectData = [@”{\”2\”:\”3\”}” dataUsingEncoding:NSUTF8StringEncoding]; NSDictionary *json = [NSJSONSerialization JSONObjectWithData:objectData options:NSJSONReadingMutableContainers error:&jsonError];
Try this: if ([myString hasPrefix:@”http”]). By the way, your test should be != NSNotFound instead of == NSNotFound. But say your URL is ftp://my_http_host.com/thing, it’ll match but shouldn’t.
Old question, but how about: NSString *newString = [[origString componentsSeparatedByCharactersInSet: [[NSCharacterSet decimalDigitCharacterSet] invertedSet]] componentsJoinedByString:@””]; It explodes the source string on the set of non-digits, then reassembles them using an empty string separator. Not as efficient as picking through characters, but much more compact in code.
In Swift 3 let data = string.data(using: .utf8) In Swift 2 (or if you already have a NSString instance) let data = string.dataUsingEncoding(NSUTF8StringEncoding) In Swift 1 (or if you have a swift String): let data = (string as NSString).dataUsingEncoding(NSUTF8StringEncoding) Also note that data is an Optional<NSData> (since the conversion might fail), so you’ll need to … Read more
If anyone is looking for a way to do this in Swift: Swift 3 introduces the Data type, with value semantics. To convert the deviceToken to a String, you can do as follows: func application(_ application: UIApplication, didRegisterForRemoteNotificationsWithDeviceToken deviceToken: Data) { let token = deviceToken.map { String(format: “%02.2hhx”, $0) }.joined() print(token) } Old answer using … Read more
NSString * result = [[array valueForKey:@”description”] componentsJoinedByString:@””];
Unfortunately, stringByAddingPercentEscapesUsingEncoding doesn’t always work 100%. It encodes non-URL characters but leaves the reserved characters (like slash / and ampersand &) alone. Apparently this is a bug that Apple is aware of, but since they have not fixed it yet, I have been using this category to url-encode a string: @implementation NSString (NSString_Extended) – (NSString … Read more