Conversion from list to string always requires an explicit decision about how the result will be formatted: which character (if any) will delimit the individual items, which delimiters (if any) will mark each item, which markers will be included at the start and end (if any) to explicitly mark the result as a list. The … Read more
>>> df.groupby(‘filename’).apply(lambda group: group.interpolate(method=’index’)) filename val1 val2 t 1 file1.csv 5 10 2 file1.csv 10 15 3 file1.csv 15 20 6 file2.csv NaN NaN 7 file2.csv 10 20 8 file2.csv 12 15
If I’m understanding your question correctly, your input “observation” data is regularly gridded? If so, scipy.ndimage.map_coordinates does exactly what you want. It’s a bit hard to understand at first pass, but essentially, you just feed it a sequence of coordinates that you want to interpolate the values of the grid at in pixel/voxel/n-dimensional-index coordinates. As … Read more
Nearest neighbor will be as fast as possible, but you will lose substantial information when resizing. Linear interpolation is less fast, but will not result in information loss unless you’re shrinking the image (which you are). Cubic interpolation (probably actually “Bicubic”) uses one of many possible formulas that incorporate multiple neighbor pixels. This is much … Read more
There are several things going on every time you make a call to scipy.interpolate.griddata: First, a call to sp.spatial.qhull.Delaunay is made to triangulate the irregular grid coordinates. Then, for each point in the new grid, the triangulation is searched to find in which triangle (actually, in which simplex, which in your 3D case will be … Read more
Here’s a reusable function you can use. It includes doctests and data validation: def bilinear_interpolation(x, y, points): ”’Interpolate (x,y) from values associated with four points. The four points are a list of four triplets: (x, y, value). The four points can be in any order. They should form a rectangle. >>> bilinear_interpolation(12, 5.5, … [(10, … Read more
You can pass anchored offsets to resample, among other options they cover this case. For example the weekly frequency from Monday: ts.resample(‘W-MON’)
You can use the += operator to append to an array. args=() for i in “$@”; do args+=(“$i”) done echo “${args[@]}” This shows how appending can be done, but the easiest way to get your desired results is: echo “$@” or args=(“$@”) echo “${args[@]}” If you want to keep your existing method, you need to … Read more
You’re getting the muddled green because of the way you’re creating your gradient in RBG space. To get a “cleaner” gradient, you can use the HSV model as mentioned in the answer of the question you linked to. RGB gradient (top) vs HSV (bottom) By scaling the H (hue) value between 0 (red) and 120 … Read more
I think this might be the easiest and safest way to do what you want in Ruby 1.9.x (sprintf doesn’t support reference by name in 1.8.x): use Kernel.sprintf feature of “reference by name”. Example: >> mystring = “There are %{thing1}s and %{thing2}s here.” => “There are %{thing1}s and %{thing2}s here.” >> vars = {:thing1 => … Read more