There seem to be many links and other such stuff, but no actual code using pipes. The advantage of using java.io.PipedInputStream and java.io.PipedOutputStream is that there is no additional consumption of memory. ByteArrayOutputStream.toByteArray() returns a copy of the original buffer, so that means that whatever you have in memory, you now have two copies of … Read more
For files generated in memory, you may use ByteArrayResource. Just convert your InputStream object using IOUtils from the Apache Commons IO library. It is quite simple: helper.addAttachment(“attachement”, new ByteArrayResource(IOUtils.toByteArray(inputStream)));
How about: Stream.continually(is.read).takeWhile(_ != -1).map(_.toByte).toArray Update: use LazyList instead of Stream (since Stream is deprecated in Scala 3) LazyList.continually(is.read).takeWhile(_ != -1).map(_.toByte).toArray
Try File file = new File(Uri.toString()); FileInputStream fileInputStream = new FileInputStream(file); Then you can read from the stream.
An InputStream ties up a tiny kernel resource, a low level file handle. In addition, the file will be locked to some extent (from delete, renaming), as long as you have it open for read. Lets imagine you didn’t care about the locked file. Eventually, if you need to read another file, and open it … Read more
Thank you @Amir for point out the log. Discovered a line: decoder->decode returned false This seems to be a common problem. Doing a search I found a solution. My previous code: URLConnection conn = url.openConnection(); conn.connect(); inputStream = conn.getInputStream(); bufferedInputStream = new BufferedInputStream(inputStream); bmp = BitmapFactory.decodeStream(bufferedInputStream); Code which is working: HttpGet httpRequest = null; try … Read more
Java 9 native implementation: byte[] data = this.getClass().getClassLoader() .getResourceAsStream(“/assets/myAsset.bin”).readAllBytes();
Below is a simple example on how to extract a ZIP File, you will need to check if the file is a directory. But this is the simplest. The step you are missing is reading the input stream and writing the contents to a buffer which is written to an output stream. // Expands the … Read more
Add Internet permission to your manifest: <uses-permission android:name=”android.permission.INTERNET”/>
Android is trying to listen on the microphone, which isn’t available on the emulator, so it fills logcat with useless stack traces. To stop this, go to the Settings app in Android, and click: Apps and notifications App permissions Microphone Then disallow microphone use for all the apps.