The form post values are stored under the name of the form in the request. For example, if you’ve overridden the getName() method of ContactType() to return “contact”, you would do this: $postData = $request->request->get(‘contact’); $name_value = $postData[‘name’]; If you’re still having trouble, try doing a var_dump() on $request->request->all() to see all the post values.
Here’s code from my app to post an image to our web server: // Dictionary that holds post parameters. You can set your post parameters that your server accepts or programmed to accept. NSMutableDictionary* _params = [[NSMutableDictionary alloc] init]; [_params setObject:[NSString stringWithString:@”1.0″] forKey:[NSString stringWithString:@”ver”]]; [_params setObject:[NSString stringWithString:@”en”] forKey:[NSString stringWithString:@”lan”]]; [_params setObject:[NSString stringWithFormat:@”%d”, userId] forKey:[NSString stringWithString:@”userId”]]; … Read more
curl’s –data will by default send Content-Type: application/x-www-form-urlencoded in the request header. However, when using Postman’s raw body mode, Postman sends Content-Type: text/plain in the request header. So to achieve the same thing as Postman, specify -H “Content-Type: text/plain” for curl: curl -X POST -H “Content-Type: text/plain” –data “this is raw data” http://78.41.xx.xx:7778/ Note that … Read more
The variable $_POST is automatically populated. Try var_dump($_POST); to see the contents. You can access individual values like this: echo $_POST[“name”]; This, of course, assumes your form is using the typical form encoding (i.e. enctype=”multipart/form-data” If your post data is in another format (e.g. JSON or XML, you can do something like this: $post = … Read more
You can use CURL for this purpose see the example code: $url = “your url”; $content = json_encode(“your data to be sent”); $curl = curl_init($url); curl_setopt($curl, CURLOPT_HEADER, false); curl_setopt($curl, CURLOPT_RETURNTRANSFER, true); curl_setopt($curl, CURLOPT_HTTPHEADER, array(“Content-type: application/json”)); curl_setopt($curl, CURLOPT_POST, true); curl_setopt($curl, CURLOPT_POSTFIELDS, $content); $json_response = curl_exec($curl); $status = curl_getinfo($curl, CURLINFO_HTTP_CODE); if ( $status != 201 ) { … Read more
It cannot be done – AFAIK. However you may use for example jquery (although you can do it with plain javascript) to serialize the form and send (using AJAX) while adding your custom header. Look at the jquery serialize which changes an HTML FORM into form-url-encoded values ready for POST. UPDATE My suggestion is to … Read more
You could have your controller action take an object which would reflect the form input names and the default model binder will automatically create this object for you: [HttpPost] public ActionResult SubmitAction(SomeModel model) { var value1 = model.SimpleProp1; var value2 = model.SimpleProp2; var value3 = model.ComplexProp1.SimpleProp1; … … return something … } Another (obviously uglier) … Read more
The $.getJSON() method does an HTTP GET and not POST. You need to use $.post() $.post(url, dataToBeSent, function(data, textStatus) { //data contains the JSON object //textStatus contains the status: success, error, etc }, “json”); In that call, dataToBeSent could be anything you want, although if are sending the contents of a an html form, you … Read more
A message has a header part and a message body separated by a blank line. The blank line is ALWAYS needed even if there is no message body. The header starts with a command and has additional lines of key value pairs separated by a colon and a space. If there is a message body, … Read more
in your return use the following: return this.Json(“you result”, JsonRequestBehavior.AllowGet);