I’m not sure how you want to use the file names, but one of these should help: If you just want to see the names, you can use something like gulp-debug, which lists the details of the vinyl file. Insert this anywhere you want a list, like so: var gulp = require(‘gulp’), debug = require(‘gulp-debug’); … Read more
By publishing your whole node_modules folder you are deploying far more files than you will actually need in production. Instead, use a task runner as part of your build process to package up those files you require, and deploy them to your wwwroot folder. This will also allow you to concat and minify your assets … Read more
Edit: Apparently gulp.watch does work with new or deleted files now. It did not when the question was asked. The rest of my answer still stands: gulp-watch is usually a better solution because it lets you perform specific actions only on the files that have been modified, while gulp.watch only lets you run complete tasks. … Read more
I sometimes also get this error when starting my gulp server. My workaround is to just run: npm rebuild node-sass And then gulp starts nicely afterward.
In gulp 3.x you could just pass the name of a task to gulp.watch() like this: gulp.task(‘watch’, function() { gulp.watch(‘app/css/*.css’, [‘styles’]); gulp.watch(‘app/js/*.js’, [‘scripts’]); gulp.watch(‘app/img/*’, [‘images’]); }); In gulp 4.x this is no longer the case. You have to pass a function. The customary way of doing this in gulp 4.x is to pass a gulp.series() … Read more
This answer might help. Task Runners (Gulp, Grunt, etc) and Bundlers (Webpack, Browserify). Why use together? …and here’s an example of using webpack from within a gulp task. This goes a step further and assumes that your webpack config is written in es6. var gulp = require(‘gulp’); var webpack = require(‘webpack’); var gutil = require(‘gutil’); … Read more
Gulp 4.0 has changed the way that tasks should be defined if the task depends on another task to execute. The list parameter has been deprecated. An example from your gulpfile.js would be: // Starts a BrowerSync instance gulp.task(‘server’, [‘build’], function(){ browser.init({server: ‘./_site’, port: port}); }); Instead of the list parameter they have introduced gulp.series() … Read more
UPDATE From later versions, there is no need to manually install gulp-util. Check the new getting started page. If you still hit this problem try reinstalling your project’s local packages: rm -rf node_modules/ npm install OUTDATED ANSWER You also need to install gulp-util: npm install gulp-util –save-dev From gulp docs- getting started (3.5): Install gulp … Read more
Your swallowError function should look like this: function swallowError (error) { // If you want details of the error in the console console.log(error.toString()) this.emit(‘end’) } I think you have to bind this function on the error event of the task that was falling, not the watch task, because that’s not where comes the problem, you … Read more
The following works without flattening the folder structure: gulp.src([‘input/folder/**/*’]).pipe(gulp.dest(‘output/folder’)); The ‘**/*’ is the important part. That expression is a glob which is a powerful file selection tool. For example, for copying only .js files use: ‘input/folder/**/*.js’