Searching for a file in all Git branches
This is one way: git log –all –name-only –pretty=format: | sort -u | grep _robot.php
grep
grep excluding file name pattern
You can quote the pattern: grep -r –exclude=”*.cmd” “ckim” ./ PS. ./ is the current directory
Pattern to get string between two specific words/characters using grep [duplicate]
Using grep -oP: s=”<some text> [email protected], <some text>” grep -oP ‘(?<=from=).*?(?=,)’ <<< “$s” [email protected] OR else avoid lookbehind by using \K: grep -oP ‘from=\K.*?(?=,)’ <<< “$s” [email protected] In case your grep doesn’t support -P (PCRE) use this sed: sed ‘s/.*from=\(.*\),.*/\1/’ <<< “$s” [email protected]
Unix Command to List files containing string but *NOT* containing another string
Try this: grep -rl <string-to-match> | xargs grep -L <string-not-to-match> Explanation: grep -lr makes grep recursively (r) output a list (l) of all files that contain <string-to-match>. xargs loops over these files, calling grep -L on each one of them. grep -L will only output the filename when the file does not contain <string-not-to-match>.
Add blank line after every result in grep
Pipe | any output to: sed G Example: ls | sed G If you man sed you will see G Append’s a newline character followed by the contents of the hold space to the pattern space.
How to display the first word of each line in my file using the linux commands?
You can use awk: awk ‘{print $1}’ your_file This will “print” the first column ($1) in your_file.
How can I ‘grep’ files in a Git repository?
Maybe you want git ls-files which lists the files in the index? (and automatically adjusts for your current directory inside the git work directory)
Surround all lines in a text file with quotes (‘something’)
Use sed? sed -e “s/\(.*\)/’\1″https://stackoverflow.com/” Or, as commented below, if the directories might contain apostrophes (nightmare if they do) use this alternate sed -e “s/”https://stackoverflow.com/”\\\\”/g;s/\(.*\)/’\1″https://stackoverflow.com/”
How to grep the last occurrence of a line pattern
I’m not sure if I got your question right, so here are some shots in the dark: Print last occurence of x (regex): grep x file | tail -1 Alternatively: tac file | grep -m1 x Print file from first matching line to end: awk ‘/x/{flag = 1}; flag’ file Print file from last matching … Read more
Grep – how to output only the content of a capturing group
This question was asked ten years ago, so I won’t mark it as duplicate. Also I noticed no sed solution was given since OP asked an answer without: sed -nr ‘s/(hello[0-9]+), please match me/\1/p’ test.txt -n stands for quiet (won’t print anything except if explicitly asked) -r allows use of extented regular expressions (avoids here … Read more