Can bash show a function’s definition?

Use type. If foobar is e.g. defined in your ~/.profile: $ type foobar foobar is a function foobar { echo “I’m foobar” } This does find out what foobar was, and if it was defined as a function it calls declare -f as explained by pmohandras. To print out just the body of the function … Read more

PHP append one array to another (not array_push or +)

array_merge is the elegant way: $a = array(‘a’, ‘b’); $b = array(‘c’, ‘d’); $merge = array_merge($a, $b); // $merge is now equals to array(‘a’,’b’,’c’,’d’); Doing something like: $merge = $a + $b; // $merge now equals array(‘a’,’b’) Will not work, because the + operator does not actually merge them. If they $a has the same … Read more

Is there a way to provide named parameters in a function call in JavaScript?

ES2015 and later In ES2015, parameter destructuring can be used to simulate named parameters. It would require the caller to pass an object, but you can avoid all of the checks inside the function if you also use default parameters: myFunction({ param1 : 70, param2 : 175}); function myFunction({param1, param2}={}){ // …function body… } // … Read more

How do I define a function with optional arguments?

Just use the *args parameter, which allows you to pass as many arguments as you want after your a,b,c. You would have to add some logic to map args->c,d,e,f but its a “way” of overloading. def myfunc(a,b, *args, **kwargs): for ar in args: print ar myfunc(a,b,c,d,e,f) And it will print values of c,d,e,f Similarly you … Read more

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