This will work even on this array: $array[0] = “hello”; $array[5] = “how”; $array[9] = “are”; end($array); echo prev($array); // will print “how” The other solutions using count() are assuming that the indexes of your array go in order; by using end and prev to move the array pointer, you get the actual values. Try … Read more
Try this, replacing .myClassName with the actual name of the class (but keep the period at the beginning). $(‘.myClassName’).each(function() { alert( this.id ); }); So if the class is “test”, you’d do $(‘.test’).each(func…. This is the specific form of .each() that iterates over a jQuery object. The form you were using iterates over any type … Read more
def altElement(a): return a[::2]
Use the shift() and push() functions: var ary = [8,1,2,3,4,5,6,7]; ary.push(ary.shift()); // results in [1, 2, 3, 4, 5, 6, 7, 8] Example: var ary = [8,1,2,3,4,5,6,7]; console.log(“Before: ” + ary); ary.push(ary.shift()); // results in [1, 2, 3, 4, 5, 6, 7, 8] console.log(“After: ” + ary);
If you can change the markup, you might want to use class instead. HTML <a class=”test” name=”Name 1″></a> <a class=”test” name=”Name 2″></a> <a class=”test” name=”Name 3″></a> JS var elements = document.getElementsByClassName(“test”); var names=””; for(var i = 0; i < elements.length; i++) { names += elements[i].name; } document.write(names); jsfiddle demo
Try myJQueryElement.get(0) or myJQueryElement[0]. (get() is most useful when you need negative indices, for example, as described in the documentation for get().)
Templates are great and if you have access to them in your project, I suggest you use them. If you’re using Underscore or Lodash it’s built in. In some cases however, you will need to build HTML in your code whether it’s refactoring or testing. I’ve found that the below format is the clearest to … Read more
import json json_data = json.dumps({ “result”:[ { “run”:[ { “action”:”stop” }, { “action”:”start” }, { “action”:”start” } ], “find”: “true” } ] }) item_dict = json.loads(json_data) print len(item_dict[‘result’][0][‘run’]) Convert it in dict.
x(end+1) = newElem is a bit more robust. x = [x newElem] will only work if x is a row-vector, if it is a column vector x = [x; newElem] should be used. x(end+1) = newElem, however, works for both row- and column-vectors. In general though, growing vectors should be avoided. If you do this … Read more
If you are lucky and need to care only for recent browsers, you can use: document.querySelectorAll(‘input[type=text]’) “recent” means not IE6 and IE7