If you want the actual HTTP Host header, see Daniel Roseman’s comment on @Phsiao’s answer. The other alternative is if you’re using the contrib.sites framework, you can set a canonical domain name for a Site in the database (mapping the request domain to a settings file with the proper SITE_ID is something you have to … Read more
You can use forloop.parentloop to get to the outer forloop, so in your case {{forloop.parentloop.counter}}.
No, because the GET parameters are not part of the URL. Simply add them to the end: <a href=”https://stackoverflow.com/questions/4591525/{% url myview %}?office=foobar”> For Django 1.5+ <a href=”https://stackoverflow.com/questions/4591525/{% url”myview’ %}?office=foobar”>
you can filter the waypoints by passing the user to the form init class waypointForm(forms.Form): def __init__(self, user, *args, **kwargs): super(waypointForm, self).__init__(*args, **kwargs) self.fields[‘waypoints’] = forms.ChoiceField( choices=[(o.id, str(o)) for o in Waypoint.objects.filter(user=user)] ) from your view while initiating the form pass the user form = waypointForm(user) in case of model form class waypointForm(forms.ModelForm): def __init__(self, … Read more
Using Django built-in template filter called title {{ “myname”|title }}
If you have any of the following tags in your template: {% load staticfiles %} {% load static from staticfiles %} {% load admin_static %} Then replace it with: {% load static %} You have to make this change because {% load staticfiles %} and {% load admin_static %} were deprecated in Django 2.1, and … Read more
First you need to prepare your url to accept the param in the regex: (urls.py) url(r’^panel/person/(?P<person_id>[0-9]+)$’, ‘apps.panel.views.person_form’, name=”panel_person_form”), So you use this in your template: {% url ‘panel_person_form’ person_id=item.id %} If you have more than one param, you can change your regex and modify the template using the following: {% url ‘panel_person_form’ person_id=item.id group_id=3 %}
Lets say your data is – data = {‘a’: [ [1, 2] ], ‘b’: [ [3, 4] ],’c’:[ [5,6]] } You can use the data.items() method to get the dictionary elements. Note, in django templates we do NOT put (). Also some users mentioned values[0] does not work, if that is the case then try … Read more
See https://docs.djangoproject.com/en/stable/ref/templates/builtins/#if : just use, to reproduce their example: {% if athlete_list %} Number of athletes: {{ athlete_list|length }} {% else %} No athletes. {% endif %}
model._meta.get_all_field_names() will give you all the model’s field names, then you can use model._meta.get_field() to work your way to the verbose name, and getattr(model_instance, ‘field_name’) to get the value from the model. NOTE: model._meta.get_all_field_names() is deprecated in django 1.9. Instead use model._meta.get_fields() to get the model’s fields and field.name to get each field name.