This is how I changed Django 1.0.2 to add ‘view’ permissions. Sorry there is no diff available. [X] 1. Added ‘view’ to default permission list #./contrib/auth/management/__init__.py def _get_all_permissions(opts): “Returns (codename, name) for all permissions in the given opts.” perms = [] for action in (‘add’, ‘change’, ‘delete’, ‘view’): perms.append((_get_permission_codename(action, opts), u’Can %s %s’ % (action, … Read more
Django has a built in groups system. Whenever you have a question like this, I recommend searching the Django docs, which are extensive, helpful, and well written. So long as you are using the django.contrib.auth app, you have access to groups. You can then assign permissions to those groups. from django.contrib.auth.models import User, Group, Permission … Read more
I’ll start this by saying we use none of these for object level permission – we use our own custom method and I really wish we hadn’t. If you can avoid object level permissions at all, do so, they are a pain to organise. This is how I evaluate the 3 apps you’ve mentioned. Active … Read more
Have a look at how to create custom permissions in the docs. class USCitizen(models.Model): # … class Meta: permissions = ( (“can_drive”, “Can drive”), (“can_vote”, “Can vote in elections”), (“can_drink”, “Can drink alcohol”), ) Then run python manage.py makemigrations && python manage.py migrate. Use the permission_required decorator to restrict access to your view.
In DRF documentation, Note: The instance-level has_object_permission method will only be called if the view-level has_permission checks have already passed Let’s assume following permission about user object List : staff only Create : anyone Retrieve : own self or staff Update, Partial update : own self or staff Destroy : staff only permissons.py from rest_framework … Read more
You need custom template tag: from django import template register = template.Library() @register.filter(name=”has_group”) def has_group(user, group_name): return user.groups.filter(name=group_name).exists() In your template: {% if request.user|has_group:”mygroup” %} <p>User belongs to my group {% else %} <p>User doesn’t belong to mygroup</p> {% endif %} Source: http://www.abidibo.net/blog/2014/05/22/check-if-user-belongs-group-django-templates/ Docs: https://docs.djangoproject.com/en/dev/howto/custom-template-tags/
South does not track django.contrib.auth permissions. See ticket #211 for more information. One of the comments on the ticket suggests that using the –all option on syncdb may solve the problem.
I suppose the first question you need to ask are what permissions do you need and what sort. By what sort, I mean do you want Model- or Object-level. To clarify the difference say you have a model Car. If you want to give permissions on all cars, then Model-level is appropriate, but if you … Read more
For those of you, who are still searching: You can create an auxiliary model with no database table. That model can bring to your project any permission you need. There is no need to deal with ContentType or create Permission objects explicitly. from django.db import models class RightsSupport(models.Model): class Meta: managed = False # No … Read more