django-admin

How to force-save an “empty”/unchanged django admin inline?

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It took me quite some time to figure out but it is actually really simple. from django.contrib import admin from django.forms.models import BaseInlineFormSet, ModelForm class AlwaysChangedModelForm(ModelForm): def has_changed(self): “”” Should returns True if data differs from initial. By always returning true even unchanged inlines will get validated and saved.””” return True class CheckerInline(admin.StackedInline): “”” Base … Read more

How do I add a link from the Django admin page of one object to the admin page of a related object?

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Use readonly_fields: class MyInline(admin.TabularInline): model = MyModel readonly_fields = [‘link’] def link(self, obj): url = reverse(…) return mark_safe(“<a href=”https://stackoverflow.com/questions/9919780/%s”>edit</a>” % url) # the following is necessary if ‘link’ method is also used in list_display link.allow_tags = True

django admin inlines: get object from formfield_for_foreignkey

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Another way, that, IMHO, feels cleaner than, but is similar to @erichonkanen’s answer is something like this: class ProjectGroupMembershipInline(admin.StackedInline): # irrelevant bits…. def formfield_for_foreignkey(self, db_field, request, **kwargs): if db_field.name == “group”: try: parent_id = request.resolver_match.args[0] kwargs[“queryset”] = Group.objects.filter(some_column=parent_id) except IndexError: pass return super().formfield_for_foreignkey(db_field, request, **kwargs)

How to register multiple models with the admin?

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admin.site.register has this definition in the library: def register(self, model_or_iterable, admin_class=None, **options): so models to be registered can be a single model or iterable object so just use this: myModels = [models.Project, models.Client, models.About] # iterable list admin.site.register(myModels) I tested this in my site and works perfectly fine.

Django InlineModelAdmin: Show partially an inline model and link to the complete model

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UPDATE: Since Django 1.8, this is built in. See this answer and the official documentation. OLD ANSWER: At the end I found a simple solution. I create a new template called linked.html that is a copy of tabular.html and I added this code to create the link. {% if inline_admin_form.original.pk %} <td class=”{{ field.field.name }}”> … Read more

Extending Django Admin Templates – altering change list

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To expand on Yuji’s answer, here are some specifics on overriding change_list_results.html … Override changelist_view as described above in step 1, and also described here at djangoproject. Or auto-override by placing in the appropriate directory as in step 2 above. (Note that the step 2 path shown above is model-specific. App-specific would be /admin/<MyAppName>/change_list.html under … Read more

Redirect on admin Save

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To change the redirect destination after save in the admin, you need to override response_add() (for adding new instances) and response_change() (for changing existing ones) in the ModelAdmin class. See the original code in django.contrib.admin.options. Quick examples to make it clearer how to do this (would be within a ModelAdmin class): from django.core.urlresolvers import reverse … Read more

Paginator for inline models in django admin

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If anyone requires this, I found this nice (though described as “quite hacky”) implementation of a pagination TabularInline subclass in this comment of a django-suit issue. For Django 1.6 it requires a template change and subclassing this PaginationInline class: from django.contrib import admin from django.contrib.admin.views.main import ChangeList from django.core.paginator import EmptyPage, InvalidPage, Paginator class InlineChangeList(object): … Read more

Is there a way to get custom Django admin actions to appear on the “change” view in addition to the “change list” view?

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Here is update and improvement of this answer. It works with django 1.6 and redirects to where you came from. class ActionInChangeFormMixin(object): def response_action(self, request, queryset): “”” Prefer http referer for redirect “”” response = super(ActionInChangeFormMixin, self).response_action(request, queryset) if isinstance(response, HttpResponseRedirect): response[‘Location’] = request.META.get(‘HTTP_REFERER’, response.url) return response def change_view(self, request, object_id, extra_context=None): actions = self.get_actions(request) … Read more

How to add the custom button which executes a Django admin action to change form page?

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You could take a look at the change_form_template and set it to a custom template of yours and override the response_change method: class MyModelAdmin(admin.ModelAdmin): # A template for a customized change view: change_form_template=”path/to/your/custom_change_form.html” def response_change(self, request, obj): opts = self.model._meta pk_value = obj._get_pk_val() preserved_filters = self.get_preserved_filters(request) if “_customaction” in request.POST: # handle the action on … Read more

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