This isn’t really a good way to structure things. Do one of the following 1) Just don’t change the return type, and override it normally in the subclass. In DerivedHandler you can return an instance of DerivedRequest using the base class signature of Request. Any client code using this can choose to cast it to … Read more
If by “illegal” you mean ill-formed, then it is illegal if the base class is inaccessible or ambiguous. It is inaccessible when, for example, the base class is private. class A {}; class B : A {}; … B b; A *pa = &b; // ERROR: base class is inaccessible Note that even in C++11 … Read more
It’s not possible, why? In C#, it is forced upon you that if you inherit public methods, you must make them public. Otherwise they expect you not to derive from the class in the first place. Instead of using the is-a relationship, you would have to use the has-a relationship. The language designers don’t allow … Read more
std::vector will manage the memory for you, like always, but this memory will be of pointers, not objects. What this means is that your classes will be lost in memory once your vector goes out of scope. For example: #include <vector> struct base { virtual ~base() {} }; struct derived : base {}; typedef std::vector<base*> … Read more