A function f :: a -> b can be “disguised” inside double continuations as a function f’ :: ((a -> r1) -> r2) -> ((b -> r1) -> r2). obfuscate :: (a -> b) -> ((a -> r1) -> r2) -> (b -> r1) -> r2 obfuscate f k2 k1 = k2 (k1 . f) … Read more
I believe that continuations are a special case of callbacks. A function may callback any number of functions, any number of times. For example: var array = [1, 2, 3]; forEach(array, function (element, array, index) { array[index] = 2 * element; }); console.log(array); function forEach(array, callback) { var length = array.length; for (var i = … Read more