One of the best known algorithms is the Boyer-Moore string searching algorithm which is O(n) although it can give sublinear performance in the best case. Which algorithm is used in Java depends on which implemetation you download. It seems that for example OpenJDK uses a naive algorithm that runs in O(nm) and linear performance in … Read more
here’s some code that might demonstrate how it works out: import java.util.ArrayList; class A { private Long id; private String name; A(Long id){ this.id = id; } @Override public boolean equals(Object v) { boolean retVal = false; if (v instanceof A){ A ptr = (A) v; retVal = ptr.id.longValue() == this.id; } return retVal; } … Read more
Since you want to see if search contains a word which is contained in the description of p you basically need to test for each value in search if it is contained in the description of p result = from p in products where search.Any(val => p.Description.Contains(val)) select p; This is c# syntax for the … Read more
You have to do it like this: If strMyString.Contains(“Something”) OrElse strMyString.Contains(“Something2”) Then ‘[Put Code Here] End if
Looking at the other attempts saddens me 🙁 public IQueryable<Part> SearchForParts(string[] query) { var q = db.Parts.AsQueryable(); foreach (var qs in query) { var likestr = string.Format(“%{0}%”, qs); q = q.Where(x => SqlMethods.Like(x.partName, likestr)); } return q; } Assumptions: partName looks like: “ABC 123 XYZ” query is { “ABC”, “123”, “XY” }
use the indexOf function if(divs[i].innerHTML.indexOf(“word”) !== -1) { // something }
“Yes”, but it won’t do what you expect. The expression used for the switch is evaluated once – in this case contains evaluates to true/false as the result (e.g. switch(true) or switch(false)) , not a string that can be matched in a case. As such, the above approach won’t work. Unless this pattern is much … Read more
SEARCH does not return 0 if there is no match, it returns #VALUE!. So you have to wrap calls to SEARCH with IFERROR. For example… =IF(IFERROR(SEARCH(“cat”, A1), 0), “cat”, “none”) or =IF(IFERROR(SEARCH(“cat”,A1),0),”cat”,IF(IFERROR(SEARCH(“22″,A1),0),”22″,”none”)) Here, IFERROR returns the value from SEARCH when it works; the given value of 0 otherwise.
I don’t think there is a built-in function that will handle what you want. You could easily write a contains() function however: function contains($str, array $arr) { foreach($arr as $a) { if (stripos($str,$a) !== false) return true; } return false; }
You use look ahead assertions to check if a string contains a word or not. If you want to assure that the string contains “Android” at some place you can do it like this: ^(?=.*Android).* You can also combine them, to ensure that it contains “Android” at some place AND “Mobile” at some place: ^(?=.*Android)(?=.*Mobile).* … Read more