Just define it in the header: template <typename T> struct S { static double something_relevant; }; template <typename T> double S<T>::something_relevant = 1.5; Since it is part of a template, as with all templates the compiler will make sure it’s only defined once.
Note: Foo me; without template arguments is legal as of C++17. See this answer: https://stackoverflow.com/a/50970942/539997. Original answer applicable before C++17: You have to do: Foo<> me; The template arguments must be present but you can leave them empty. Think of it like a function foo with a single default argument. The expression foo won’t call … Read more
No. Whatever changes the paper will entail, which is little at this point, it cannot change the fact that a non-template function definition is only typed once. Moreover, if your proposed code would be legal, we could presumably find a way to declare a variable of type std::integral_constant<int, i>, which feels very prohibitive in terms … Read more
Write this: template <class T> template <class U> void MyClass<T>::foo() { /* … */ }