I have been the same problem. It seems an Angular tricks: If you remove leading slash in ‘redirectTo’ field, your application will be redirected successfully to auth/sign-in. Use this in app.routing: const routes: Routes = [ {path: ”, redirectTo: ‘auth’, pathMatch: ‘full’}, ]; ‘redirectTo’ value starts with a ‘/’ = absolute path ‘redirectTo’ value starts … Read more
Just to complete the original answer, I think it is clearer adding the nested style inside the parent like that: <Style x:Key=”WindowHeader” TargetType=”DockPanel” > <Setter Property=”Background” Value=”AntiqueWhite”></Setter> <Style.Resources> <Style TargetType=”Image”> <Setter Property=”Margin” Value=”6″></Setter> <Setter Property=”Width” Value=”36″></Setter> <Setter Property=”Height” Value=”36″></Setter> </Style> <Style TargetType=”TextBlock”> <Setter Property=”TextWrapping” Value=”Wrap”></Setter> </Style> </Style.Resources> </Style>
You could consider using CSS clip: rect(top, right, bottom, left); to clip a fixed positioned element to a parent. See demo at http://jsfiddle.net/lmeurs/jf3t0fmf/. Beware, use with care! Though the clip style is widely supported, main disadvantages are that: The parent’s position cannot be static or relative (one can use an absolutely positioned parent inside a … Read more
The best way with the HTML you have would probably be to use the next function, like so: var div = $(this).next(‘.class2’); Since the click handler is happening to the <a>, you could also traverse up to the parent DIV, then search down for the second DIV. You would do this with a combination of … Read more
The variable children is a NodeList instance and NodeLists are not true Array and therefore they do not inherit the forEach method. Also some browsers actually support it nodeList.forEach ES5 You can use slice from Array to convert the NodeList into a proper Array. var array = Array.prototype.slice.call(children); You could also simply use call to … Read more
I’ve done this before. I laid down a lot of paper towels on a table, and got out a loaf of (cheap) bread, a small tub of butter, a small jar of jelly, and a plastic butter knife. I said to the kids, “How many of you think computers are smart?” Most of them raised … Read more
if ( $(‘#myfav’).children().length > 0 ) { // do something } This should work. The children() function returns a JQuery object that contains the children. So you just need to check the size and see if it has at least one child.
Sounds like you’re overthinking it. You’ve observed the difference between childNodes and children, which is that childNodes contains all nodes, including text nodes consisting entirely of whitespace, while children is a collection of just the child nodes that are elements. That’s really all there is to it. There is nothing unpredictable about either collection, although … Read more