s3 urls – get bucket name and path
Since it’s just a normal URL, you can use urlparse to get all the parts of the URL. >>> from urlparse import urlparse >>> o = urlparse(‘s3://bucket_name/folder1/folder2/file1.json’, allow_fragments=False) >>> o ParseResult(scheme=”s3″, netloc=”bucket_name”, path=”/folder1/folder2/file1.json”, params=””, query=”, fragment=””) >>> o.netloc ‘bucket_name’ >>> o.path ‘/folder1/folder2/file1.json’ You may have to remove the beginning slash from the key as the … Read more