An Array{Bool} stores each true/false value as a Bool, which is represented internally as a UInt8. So if your array has N elements, it will take N bytes to store it. A BitArray stores each true/false value as a single bit, with (conceptually) 8 of them packed into a single UInt8. Consequently, it takes only … Read more
Here’s one I whipped up: UPDATE – something about this class had been bothering me all day – it wasn’t size based – creating a BitArray with N slots/bits was a two step operation – instantiate, resize. Updated the class to be size based with an optional second paramter for populating the size based instance … Read more
This should work: byte ConvertToByte(BitArray bits) { if (bits.Count != 8) { throw new ArgumentException(“bits”); } byte[] bytes = new byte[1]; bits.CopyTo(bytes, 0); return bytes[0]; }
As selected answer says you can use findAndModify to generate sequential IDs. But I strongly disagree with opinion that you should not do that. It all depends on your business needs. Having 12-byte ID may be very resource consuming and cause significant scalability issues in future. I have detailed answer here.
If I am not too late, this page gives awesome explanation with examples. An array of int can be used to deal with array of bits. Assuming size of int to be 4 bytes, when we talk about an int, we are dealing with 32 bits. Say we have int A[10], means we are working … Read more
If you mainly want to be able to name your bit fields and easily manipulate them, e.g. to work with flags represented as single bits in a communications protocol, then you can use the standard Structure and Union features of ctypes, as described at How Do I Properly Declare a ctype Structure + Union in … Read more