From the readme word doc for RC1 (not indexed by google) ASP.NET Compiler Post-Build Step Currently, errors within a view file are not detected until run time. To let you detect these errors at compile time, ASP.NET MVC projects now include an MvcBuildViews property, which is disabled by default. To enable this property, open the … Read more
I think you can make this work using jQuery’s .on event handler. Here’s a fiddle you can test; just make sure to expand the HTML frame in the fiddle as much as possible so you can view the modal. http://jsfiddle.net/8c05pn1f/ HTML <p>Link 1</p> <a data-toggle=”modal” data-id=”ISBN564541″ title=”Add this item” class=”open-AddBookDialog btn btn-primary” href=”#addBookDialog”>test</a> <p> </p> <p>Link … Read more
Here’s how I do it. I decided to use IPrincipal instead of IIdentity because it means I don’t have to implement both IIdentity and IPrincipal. Create the interface interface ICustomPrincipal : IPrincipal { int Id { get; set; } string FirstName { get; set; } string LastName { get; set; } } CustomPrincipal public class … Read more
You can just use the ContentResult to return a plain string: public ActionResult Temp() { return Content(“Hi there!”); } ContentResult by default returns a text/plain as its contentType. This is overloadable so you can also do: return Content(“<xml>This is poorly formatted xml.</xml>”, “text/xml”);
You can pass the id as part of the routeValues parameter of the RedirectToAction() method. return RedirectToAction(“Action”, new { id = 99 }); This will cause a redirect to Site/Controller/Action/99. No need for temp or any kind of view data.
NOTE: this answer applies only to Web services, if you are returning JSON from a Controller method, make sure you read this SO answer below as well: https://stackoverflow.com/a/7207539/1246870 The MaxJsonLength property cannot be unlimited, is an integer property that defaults to 102400 (100k). You can set the MaxJsonLength property on your web.config: <configuration> <system.web.extensions> <scripting> … Read more
For MVC v5.1 use Html.EnumDropDownListFor @Html.EnumDropDownListFor( x => x.YourEnumField, “Select My Type”, new { @class = “form-control” }) For MVC v5 use EnumHelper @Html.DropDownList(“MyType”, EnumHelper.GetSelectList(typeof(MyType)) , “Select My Type”, new { @class = “form-control” }) For MVC 5 and lower I rolled Rune’s answer into an extension method: namespace MyApp.Common { public static class MyExtensions{ … Read more
Here is a mostly clean attribute-based solution to the multiple submit button issue based heavily on the post and comments from Maarten Balliauw. [AttributeUsage(AttributeTargets.Method, AllowMultiple = false, Inherited = true)] public class MultipleButtonAttribute : ActionNameSelectorAttribute { public string Name { get; set; } public string Argument { get; set; } public override bool IsValidName(ControllerContext controllerContext, … Read more
You don’t use a file input control. Server side controls are not used in ASP.NET MVC. Checkout the following blog post which illustrates how to achieve this in ASP.NET MVC. So you would start by creating an HTML form which would contain a file input: @using (Html.BeginForm(“Index”, “Home”, FormMethod.Post, new { enctype = “multipart/form-data” })) … Read more
Html.Partial returns a String. Html.RenderPartial calls Write internally and returns void. The basic usage is: // Razor syntax @Html.Partial(“ViewName”) @{ Html.RenderPartial(“ViewName”); } // WebView syntax <%: Html.Partial(“ViewName”) %> <% Html.RenderPartial(“ViewName”); %> In the snippet above, both calls will yield the same result. While one can store the output of Html.Partial in a variable or return … Read more