The variable $id isn’t in the scope of the function. You need to use the use clause to make external variables accessible: $foo = array_filter($bar, function($obj) use ($id) { if (isset($obj->foo)) { var_dump($id); if ($obj->foo == $id) return true; } return false; });
array_filter should work fine if you use the identical comparison operator. here’s an example $values = [NULL, FALSE, ”, 0, 1]; function myFilter($var){ return ($var !== NULL && $var !== FALSE && $var !== ”); } $res = array_filter($values, ‘myFilter’); Or if you don’t want to define a filtering function, you can also use an … Read more
Functional approach: $array = array_filter($array, function($key) { return strpos($key, ‘foo-‘) === 0; }, ARRAY_FILTER_USE_KEY); Procedural approach: $only_foo = array(); foreach ($array as $key => $value) { if (strpos($key, ‘foo-‘) === 0) { $only_foo[$key] = $value; } } Procedural approach using objects: $i = new ArrayIterator($array); $only_foo = array(); while ($i->valid()) { if (strpos($i->key(), ‘foo-‘) === … Read more