Swift: Sort array of objects alphabetically

In the closure you pass to sort, compare the properties you want to sort by. Like this:

movieArr.sorted { $0.name < $1.name }

or the following in the cases that you want to bypass cases:

movieArr.sorted { $0.name.lowercased() < $1.name.lowercased() }

Sidenote: Typically only types start with an uppercase letter; I’d recommend using name and date, not Name and Date.

Example, in a playground:

class Movie {
    let name: String
    var date: Int?
    
    init(_ name: String) {
        self.name = name
    }
}

var movieA = Movie("A")
var movieB = Movie("B")
var movieC = Movie("C")

let movies = [movieB, movieC, movieA]
let sortedMovies = movies.sorted { $0.name < $1.name }
sortedMovies

sortedMovies will be in the order [movieA, movieB, movieC]

Swift5 Update

channelsArray = channelsArray.sorted { (channel1, channel2) -> Bool in
            let channelName1 = channel1.name
            let channelName2 = channel2.name
            return (channelName1.localizedCaseInsensitiveCompare(channelName2) == .orderedAscending)
}