Ruby – Keyword Arguments – Can you treat all of the keyword arguments as a hash? How?

Yes, this is possible, but it’s not very elegant.

You’ll have to use the parameters method, which returns an array of the method’s parameters and their types (in this case we only have keyword arguments).

def foo(one: 1, two: 2, three: 3)
  method(__method__).parameters
end  
#=> [[:key, :one], [:key, :two], [:key, :three]]

Knowing that, there’s various ways how to use that array to get a hash of all the parameters and their provided values.

def foo(one: 1, two: 2, three: 3)
  params = method(__method__).parameters.map(&:last)
  opts = params.map { |p| [p, eval(p.to_s)] }.to_h
end
#=> {:one=>1, :two=>2, :three=>3}

So your example would look like

def method(name: nil, color: nil, shoe_size: nil)
  opts = method(__method__).parameters.map(&:last).map { |p| [p, eval(p.to_s)] }.to_h
  SomeOtherObject.some_other_method(opts)
end

Think carefully about using this. It’s clever but at the cost of readability, others reading your code won’t like it.

You can make it slightly more readable with a helper method.

def params # Returns the parameters of the caller method.
  caller_method = caller_locations(length=1).first.label  
  method(caller_method).parameters 
end

def method(name: nil, color: nil, shoe_size: nil)
  opts = params.map { |p| [p, eval(p.to_s)] }.to_h
  SomeOtherObject.some_other_method(opts)
end

Update: Ruby 2.2 introduced Binding#local_variables which can be used instead of Method#parameters. Be careful because you have to call local_variables before defining any additional local variables inside the method.

# Using Method#parameters
def foo(one: 1, two: 2, three: 3)
  params = method(__method__).parameters.map(&:last)
  opts = params.map { |p| [p, eval(p.to_s)] }.to_h
end
#=> {:one=>1, :two=>2, :three=>3}

# Using Binding#local_variables (Ruby 2.2+)
def bar(one: 1, two: 2, three: 3)
  binding.local_variables.params.map { |p|
    [p, binding.local_variable_get(p)]
  }.to_h
end
#=> {:one=>1, :two=>2, :three=>3}