I know what you are trying to do, but its not what you want.
First, unless you are changing data on the server, don’t use a POST request. Just have #see_comments be a normal <a href="https://stackoverflow.com/comments.php?aid=1">...
If you have to use POST, then do this to get the page to follow your call:
$("#see_comments").click(function() {
$('<form action="comments.php" method="POST">' +
'<input type="hidden" name="aid" value="' + imgnum + '">' +
'</form>').submit();
});
How this would actually work.
First $.post is only an AJAX method and cannot be used to do a traditional form submit like you are describing. So, to be able to post a value and navigate to the new page, we need to simulate a form post.
So the flow is as follows:
- You click on the image, and your JS code gets the
imgnum - Next, someone clicks on
#see_comments - We create a temporary
formwith theimgnumvalue in it as a hidden field - We submit that form, which posts the value and loads the
comments.phppage - Your
comments.phppage will have access to the posted variable (i.e. in PHP it would be$_POST['aid'])