LINQ to Get Closest Value?

July 31, 2023 by Tarik

Try sorting them by the absolute value of the difference between the number and 21 and then take the first item:

float closest = MyStuff
    .Select (n => new { n, distance = Math.Abs (n - 21) })
    .OrderBy (p => p.distance)
    .First().n;

Or shorten it according to @Yuriy Faktorovich’s comment:

float closest = MyStuff
    .OrderBy(n => Math.Abs(n - 21))
    .First();