How to produce a range with step n in bash? (generate a sequence of numbers with increments)

I’d do

for i in `seq 0 2 10`; do echo $i; done

(though of course seq 0 2 10 will produce the same output on its own).

Note that seq allows floating-point numbers (e.g., seq .5 .25 3.5) but bash’s brace expansion only allows integers.