How to find if a Scala String is parseable as a Double or not?

For Scala 2.13+ see Xavier’s answer below. Apparently there’s a toDoubleOption method now.

For older versions:

def parseDouble(s: String) = try { Some(s.toDouble) } catch { case _ => None }

Fancy version (edit: don’t do this except for amusement value; I was a callow youth years ago when I used to write such monstrosities):

case class ParseOp[T](op: String => T)
implicit val popDouble = ParseOp[Double](_.toDouble)
implicit val popInt = ParseOp[Int](_.toInt)
// etc.
def parse[T: ParseOp](s: String) = try { Some(implicitly[ParseOp[T]].op(s)) } 
                                   catch {case _ => None}

scala> parse[Double]("1.23")
res13: Option[Double] = Some(1.23)

scala> parse[Int]("1.23")
res14: Option[Int] = None

scala> parse[Int]("1")
res15: Option[Int] = Some(1)