Update
As Martin R states in the comments, tuples with up to six components can now be compared with ==. Tuples with different component counts or different component types are considered to be different types so these cannot be compared, but the code for the simple case I described below is now obsolete.
Try this:
func == <T:Equatable> (tuple1:(T,T),tuple2:(T,T)) -> Bool
{
return (tuple1.0 == tuple2.0) && (tuple1.1 == tuple2.1)
}
It’s exactly the same as yours, but I called it ==. Then things like:
(1, 1) == (1, 1)
are true and
(1, 1) == (1, 2)
are false