How is `x = 42; x = lambda: x` parsed? [duplicate]

Question

The variable x is created by the first assignment, and rebound with the second assignment.

Since the x in the lambda isn’t evaluated until the lambda is called, calling it will evaluate to the most recently assigned value.

Note that this is not dynamic scoping – if it were dynamic, the following would print “99”, but it prints “<function …”:

x = 42
x = lambda: x

def test(f):
  x = 99
  print(f())

test(x)