How do I specify that a non-generic Swift type should comply to a protocol?

Question

Is swift you must use generics, in this way:

Given these example declarations of protocol, main class and subclass:

protocol ExampleProtocol {
    func printTest()   // classes that implements this protocol must have this method
}

// an empty test class
class ATestClass
{

}

// a child class that implements the protocol
class ATestClassChild : ATestClass, ExampleProtocol
{
    func printTest()
    {
        println("hello")
    }
}

Now, you want to define a method that takes an input parameters of type ATestClass (or a child) that conforms to the protocol ExampleProtocol.
Write the method declaration like this:

func addFilter<T where T: ATestClass, T: ExampleProtocol>(newFilter: T)
{
    println(newFilter)
}

Your method, redefined in swift, should be

func addFilter<T where T:GPUImageOutput, T:GPUImageInput>(newFilter:T!)
{
    // ...
}

EDIT:

as your last comment, an example with generics on an Enum

    enum OptionalValue<T> {
        case None
        case Some(T)
    }
    var possibleInteger: OptionalValue<Int> = .None
    possibleInteger = .Some(100)

Specialized with protocol conformance:

    enum OptionalValue<T where T:GPUImageOutput, T:GPUImageInput> {
        case None
        case Some(T)
    }

EDIT^2:

you can use generics even with instance variables:

Let’s say you have a class and an instance variable, you want that this instance variable takes only values of the type ATestClass and that conforms to ExampleProtocol

class GiveMeAGeneric<T: ATestClass where T: ExampleProtocol>
{
    var aGenericVar : T?
}

Then instantiate it in this way:

    var child = ATestClassChild()
    let aGen = GiveMeAGeneric<ATestClassChild>()
    aGen.aGenericVar = child

If child doesn’t conform to the protocol ExampleProtocol, it won’t compile

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