css :nth-child() :after

You can, but you are doing it wrong..

The issue that that all your p elements are inside li. So all of them are the first child of their li container.

You will need to put the nth-child on the li elements.

#id li:nth-child(1) p:after,
#id li:nth-child(2) p:after,
#id li:nth-child(3) p:after {
    content: 'OM';
    color: pink;
}

#id li:nth-child(4) p:after,
#id li:nth-child(5) p:after,
#id li:nth-child(6) p:after {
    content: 'Nom';
    color: blue;
}

Quoting the W3C documentation

The :nth-child(an+b) pseudo-class notation represents an element that has an+b-1 siblings before it in the document tree, for any positive integer or zero value of n, and has a parent element.

Update 1

You could also simplify this by using

#id li:nth-child(-n+3) p:after {
    content: 'OM';
    color: pink;
}

#id li:nth-last-child(-n+3) p:after { /*this means last 3*/
    content: 'Nom';
    color: blue;
}

Demo at http://jsfiddle.net/gaby/4H4AS/2/

Update 2

If you want the first six only to be different (and not first 3 and last 3) you could

#id li:nth-child(-n+6) p:after { /*this means first 6*/
    content: 'Nom';
    color: blue;
}

#id li:nth-child(-n+3) p:after {/*this means first 3 and since it comes second it has precedence over the previous for the common elements*/
    content: 'OM';
    color: pink;
}

Demo at http://jsfiddle.net/gaby/4H4AS/3/