Use the int function to get the integer part of the result, truncated toward 0. This produces the nearest integer to the result, located between the result and 0. For example, int(3/2) is 1, int(-3/2) is -1. Source: The AWK Manual – Numeric Functions
In awk, Since 1 always evaluates to true, it performs default operation {print $0}, hence prints the current line stored in $0 So, awk ‘$2==”no”{$3=”N/A”}1’ file is equivalent to and shorthand of awk ‘$2==”no”{$3=”N/A”} {print $0}’ file Again $0 is default argument to print, so you could also write awk ‘$2==”no”{$3=”N/A”} {print}’ file In-fact you … Read more
awk ‘{print substr($0,2,6)}’ file the syntax for substr() is substr(string,start index,length)
Yes. There’s logical OR || that you can use: awk ‘{if ($2==”abc” || $2==”def”) print “blah” }’
You should use the printf AWK statement. That way you can specify padding, precision, etc. In your case, the %f control letter seems the more appropriate.
Besides the awk answer by @Jerry, there are other alternatives: Using cut (assumes tab delimiter by default): cut -f32-58 foo >bar Using perl: perl -nle ‘@a=split;print join “\t”, @a[31..57]’ foo >bar
Note: Coprocess is GNU awk specific. Anyway another alternative is using getline cmd = “strip “$1 while ( ( cmd | getline result ) > 0 ) { print result } close(cmd) Calling close(cmd) will prevent awk to throw this error after a number of calls : fatal: cannot open pipe `…’ (Too many open files)
NR starts at 1, so use awk ‘{print NR-1 “,” $0}’
Yes, you can use the shell variables inside awk. There are a bunch of ways of doing it, but my favorite is to define a variable with the -v flag: $ echo | awk -v my_var=4 ‘{print “My var is ” my_var}’ My var is 4 Just pass the environment variable as a parameter to … Read more
When you split an array, the number of elements is returned, so you can say: echo “hello world” | awk ‘{n=split($0, array, ” “)} END{print n }’ # ————————^^^——————————–^^ Output is: 2